See the SPARQL spec for the exact syntax for REPLACE:
REPLACE(str(?YourVariable), '^.*(/|#)', '')
AS assigns a variable so it is setting ?localName. You can not also use
it in the pattern (variables are set once per solution).
You will need to change ?YourVariable.
And "?Desvio rdfs:label ?localName."
Andy
On 23/07/13 18:48, Anthony Ramalho wrote:
Hi Andy,
I tried this (based on what you suggested):
PREFIX hazop:<http://www.owl-ontologies.com/Ontology1372961464.owl#>
PREFIX rdfs:<http://www.w3.org/2000/01/rdf-schema#>
SELECT ?No ?Desvio (REPLACE(str(?YourVariable), '^.*(/|#)') AS ?localName)
WHERE { ?No hazop:hasDeviation ?Desvio.
?Desvio rdfs:label ?localName.}
It didn't work and I got this error message:
Exception in thread "main" com.hp.hpl.jena.query.QueryParseException: Lexical error at line 1,
column 147. Encountered: "(" (40), after : "REPLACE"
at com.hp.hpl.jena.sparql.lang.ParserSPARQL11.perform(ParserSPARQL11.java:96)
at com.hp.hpl.jena.sparql.lang.ParserSPARQL11.parse(ParserSPARQL11.java:40)
at com.hp.hpl.jena.query.QueryFactory.parse(QueryFactory.java:132)
at com.hp.hpl.jena.query.QueryFactory.create(QueryFactory.java:69)
at com.hp.hpl.jena.query.QueryFactory.create(QueryFactory.java:40)
at com.hp.hpl.jena.query.QueryFactory.create(QueryFactory.java:28)
at testesontologia.TestesOntologiaHazop.main(TestesOntologiaHazop.java:91)
Thank you for your help,
Anthony Diniz
________________________________
From: Andy Seaborne <a...@apache.org>
To: users@jena.apache.org
Sent: Tuesday, July 23, 2013 2:03 PM
Subject: Re: Doubt about SPARQL
On 23/07/13 17:53, Anthony Diniz wrote:
Thank you, Joshua.
My case is the 3rd one. Can you give me an example? I have foo:someIndividual, but I
would like just "someIndividual", without having to process the answer as
string with Java.
Thank you again,
Anthony
REPLACE(str(?YourVariable), '^.*(/|#)')
will calculate the local part for your example.
SELECT ... ?localName {
...
BIND(REPLACE(str(?YourVariable), '^.*(/|#)') AS ?localName)
....
}
or
SELECT ... (REPLACE(str(?YourVariable), '^.*(/|#)') AS ?localName)
WHERE
{ ... }
Enviado via iPhone
Em 2013-07-23, às 12:24, Joshua TAYLOR <joshuaaa...@gmail.com> escreveu:
On Tue, Jul 23, 2013 at 9:57 AM, Anthony Ramalho
<anthony_and...@yahoo.com> wrote:
I'd like to know if somebody knows a way of hiding the prefix from results in
SPARQL queries.
If yes, is it possible showing some kind of example?
What do you mean by "hiding the prefix"?
And how are you processing the results? Using ResultSetFormatter?
1) Are you currently getting results like: foo:someIndividual but you
want <http://foo.com/.../someIndividual>, i.e., you want to to show
the full IRI, and not use a prefix?
2) Are you currently getting results like
<http://foo.com/.../someIndividual> and you want to hide the prefix
(of the IRI) "http://foo.com/.../"; and show foo:someIndividual
instead?
3) Are you currently getting results like
<http://foo.com/.../someIndividual> or foo:someIndividual, and you
want to just have someIndividual instead?
All three are possible, but they require different approaches.
//JT
--
Joshua Taylor, http://www.cs.rpi.edu/~tayloj/
