That would only count triples in the default graph and omit triples in named graphs. To account for them, you would need something like
SELECT (COUNT(*) AS ?no) { { ?s ?p ?o } UNION { GRAPH ?g { ?s ?p ?o } } } On Mon, Nov 9, 2015 at 3:47 PM, Zen 98052 <z98...@outlook.com> wrote: > What is the most efficient way to get total number of triples? > > Is this query below the only way? > > SELECT (COUNT(*) AS ?no) { ?s ?p ?o } > > > Thanks, > > Z