You should call PythonOps.IsSubClass and pass in the PythonType and the interface you want to compare it with. The interface can be either a .NET type object or another Python type object (or a tuple, etc...)
The not raising on missing functions is a feature :) You could build a meta-class which would look at the incoming arguments and validate that all of the methods in an interface are implemented. That shouldn't be too hard - probably just seomthing like: assert (set(dir(someInterface)) & set(newTypeDict)) == set(dir(someInterface)) -----Original Message----- From: users-boun...@lists.ironpython.com [mailto:users-boun...@lists.ironpython.com] On Behalf Of Jeff Slutter Sent: Monday, December 15, 2008 12:15 PM To: Discussion of IronPython Subject: [IronPython] Determine the classes/interfaces a Python implements I have a Python script that creates a class within it. This Python class is derived off of a class, or interface, I made in C# - something like: class MyClass(Test.MainForm.IScript): ... Now, back in C#, I have gotten access to "MyClass" by: object myclass = someScope.GetVariable("MyClass"); Is there a way to determine either: a) what classes/interfaces MyClass implements OR b) if it implements a specific class/interface I want to know if the "object myclass" is supposed to implement Test.MainForm.IScript or not. I don't want to create an instance of MyClass as this would cause problems, executing things I'm not ready to execute. Also, related but not as important, implementing an interface (as above) doesn't cause any compiler errors if I'm missing functions - is there a way to enforce this? Thanks, Jeff _______________________________________________ Users mailing list Users@lists.ironpython.com http://lists.ironpython.com/listinfo.cgi/users-ironpython.com _______________________________________________ Users mailing list Users@lists.ironpython.com http://lists.ironpython.com/listinfo.cgi/users-ironpython.com
