Hi. I’m trying to use RTPENGINE + OPENSIPS to connect a RTP PBX with a External SRTP.
For this I’m using RTPENGINE module. Questions. Is there a way to indicate to RTPENGINE to use certain cypher suite?. Now, I hace in the offer : m=audio 62768 RTP/SAVP 120 9 0 8 18 101 a=rtpmap:120 opus/48000/2 a=fmtp:120 useinbandfec=1; usedtx=1; maxaveragebitrate=64000 a=rtpmap:18 G729/8000 a=fmtp:18 annexb=yes a=rtpmap:101 telephone-event/8000 a=fmtp:101 0-15 a=crypto:1 AES_256_CM_HMAC_SHA1_80 inline:dVwYFc1ARkmoeVkPN9JdKXYbJHEA1womGZ3X4gvs3rGZHQew3AaHURWjvO6YtA== a=crypto:2 AES_256_CM_HMAC_SHA1_32 inline:oSgNVYgBtcnf9/tRduZ/3LUgTwqQMfUsOyQcZutOAnBhb+kOdtLN/o6Ezt/e/Q== a=crypto:3 AES_CM_128_HMAC_SHA1_80 inline:PEwsve6fAIxUVHbBnhLZb303atLbFpw193GkTn/Q a=crypto:4 AES_CM_128_HMAC_SHA1_32 inline:XRtaI0RO1Sfhaf8ZstLX5eRUF07y0vIcv9iAOVhC a=sendrecv And then in the ANSWER from RTPENGINE. o=root 2039350566 2039350566 IN IP4 64.76.XXX.94 s=GHJ c=IN IP4 64.76.XXX.133 t=0 0 m=audio 10674 RTP/SAVP 0 101 a=maxptime:150 a=rtpmap:0 PCMU/8000 a=rtpmap:101 telephone-event/8000 a=fmtp:101 0-16 a=sendrecv a=rtcp:10675 a=crypto:1 AES_256_CM_HMAC_SHA1_80 inline:mObON802Wis2GH0puTCaOznh7as+BTpu1IBZAzNcocQFn95N9YGuZRZ7dNWcyA Second. I’m getting an error in the UA client with SRTP. Indicating this: 2020-11-25 16:45:20.755 | DEBUG | 104875 RemoteParticipant::adjustRTPStreams(): Crypto Suite: SRTP_AES_256_CM_HMAC_SHA1_80 Cipher Key Length: 46 SDP Cipher Key Length: 45 2020-11-25 16:45:20.755 | INFO | 104875 RemoteParticipant::adjustRTPStreams(): SDES crypto key found in SDP, but is not of correct length after base 64 decode: 45, should be: 46 Could it be that the cipher key length calculated by RTPENGINE is cut? Or maybe I’m missing something? Is possible that maybe my Centos 7 is cutting the message ? On the other hand, is possible to force rtpengine to use another of the cipher suites? a=crypto:1 AES_256_CM_HMAC_SHA1_80 inline:dVwYFc1ARkmoeVkPN9JdKXYbJHEA1womGZ3X4gvs3rGZHQew3AaHURWjvO6YtA== a=crypto:2 AES_256_CM_HMAC_SHA1_32 inline:oSgNVYgBtcnf9/tRduZ/3LUgTwqQMfUsOyQcZutOAnBhb+kOdtLN/o6Ezt/e/Q== a=crypto:3 AES_CM_128_HMAC_SHA1_80 inline:PEwsve6fAIxUVHbBnhLZb303atLbFpw193GkTn/Q a=crypto:4 AES_CM_128_HMAC_SHA1_32 inline:XRtaI0RO1Sfhaf8ZstLX5eRUF07y0vIcv9iAOVhC Does someone have any idea here? Thanks in advance, Best Regards, *Ricardo Martinez*
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