Check the dynamical matrix file, produced by ph.x at the end of the run, there you will also have the phonon displacements.
kind regards On 22 September 2014 18:27, Said Asma <saidasma1987 at yahoo.fr> wrote: > Dear QE users ans developers, > > I did the phonons calculation of the binary AlN (rocksalt) with 16 atoms . > > My output files is as following: > > Diagonalizing the dynamical matrix > > q = ( 0.000000000 0.000000000 0.000000000 ) > > ************************************************************************** > freq ( 1) = 1.108833 [THz] = 36.986674 [cm-1] > freq ( 2) = 1.574620 [THz] = 52.523675 [cm-1] > freq ( 3) = 1.575398 [THz] = 52.549629 [cm-1] > freq ( 4) = 8.195754 [THz] = 273.380916 [cm-1] > freq ( 5) = 8.196815 [THz] = 273.416304 [cm-1] > freq ( 6) = 8.199734 [THz] = 273.513674 [cm-1] > freq ( 7) = 8.200351 [THz] = 273.534269 [cm-1] > freq ( 8) = 8.201724 [THz] = 273.580054 [cm-1] > freq ( 9) = 8.204042 [THz] = 273.657390 [cm-1] > freq ( 10) = 8.204069 [THz] = 273.658277 [cm-1] > freq ( 11) = 8.204305 [THz] = 273.666167 [cm-1] > freq ( 12) = 9.560810 [THz] = 318.914296 [cm-1] > freq ( 13) = 9.561375 [THz] = 318.933138 [cm-1] > freq ( 14) = 9.564736 [THz] = 319.045240 [cm-1] > freq ( 15) = 9.565551 [THz] = 319.072451 [cm-1] > freq ( 16) = 9.568429 [THz] = 319.168422 [cm-1] > freq ( 17) = 9.569095 [THz] = 319.190663 [cm-1] > freq ( 18) = 12.351077 [THz] = 411.987578 [cm-1] > freq ( 19) = 12.431223 [THz] = 414.660977 [cm-1] > freq ( 20) = 12.439828 [THz] = 414.947983 [cm-1] > freq ( 21) = 12.782122 [THz] = 426.365702 [cm-1] > freq ( 22) = 12.796523 [THz] = 426.846069 [cm-1] > freq ( 23) = 12.854425 [THz] = 428.777481 [cm-1] > freq ( 24) = 12.908753 [THz] = 430.589665 [cm-1] > freq ( 25) = 12.916648 [THz] = 430.852986 [cm-1] > freq ( 26) = 12.923203 [THz] = 431.071665 [cm-1] > freq ( 27) = 12.940057 [THz] = 431.633836 [cm-1] > freq ( 28) = 12.951841 [THz] = 432.026913 [cm-1] > freq ( 29) = 13.043933 [THz] = 435.098776 [cm-1] > freq ( 30) = 13.090098 [THz] = 436.638683 [cm-1] > freq ( 31) = 13.091268 [THz] = 436.677691 [cm-1] > freq ( 32) = 16.509761 [THz] = 550.706361 [cm-1] > freq ( 33) = 16.566717 [THz] = 552.606181 [cm-1] > freq ( 34) = 16.587373 [THz] = 553.295203 [cm-1] > freq ( 35) = 16.640103 [THz] = 555.054089 [cm-1] > freq ( 36) = 16.658006 [THz] = 555.651280 [cm-1] > freq ( 37) = 16.692001 [THz] = 556.785223 [cm-1] > freq ( 38) = 19.936035 [THz] = 664.994532 [cm-1] > freq ( 39) = 19.939099 [THz] = 665.096767 [cm-1] > freq ( 40) = 19.940916 [THz] = 665.157356 [cm-1] > freq ( 41) = 19.955181 [THz] = 665.633197 [cm-1] > freq ( 42) = 21.966886 [THz] = 732.736442 [cm-1] > freq ( 43) = 21.984557 [THz] = 733.325899 [cm-1] > freq ( 44) = 22.013871 [THz] = 734.303712 [cm-1] > freq ( 45) = 22.697394 [THz] = 757.103583 [cm-1] > freq ( 46) = 22.729742 [THz] = 758.182599 [cm-1] > freq ( 47) = 22.771292 [THz] = 759.568539 [cm-1] > freq ( 48) = 22.788849 [THz] = 760.154171 [cm-1] > *********************************************************************** > > It has 16 atoms then we have 48 frequencies, 3 acoustic (which tend to 0) > and 46 optical frenquencies, but how can I differentiate between > longitudinal and transverse waves frequency? > > with respectful regards > Said Asma > > *********************************************** > Said Asma, > PhD. LMCN, > Facult? des sciences de Monastir, > Avenue de l'environnement 5019-Monastir,Tunisie > E-mail :saidasma1987 at yahoo.fr > *********************************************** > > _______________________________________________ > Pw_forum mailing list > Pw_forum at pwscf.org > http://pwscf.org/mailman/listinfo/pw_forum > -- Dr. Lorenzo Paulatto IdR @ IMPMC -- CNRS & Universit? Paris 6 phone: +33 (0)1 44275 084 / skype: paulatz www: http://www-int.impmc.upmc.fr/~paulatto/ mail: 23-24/4?16 Bo?te courrier 115, 4 place Jussieu 75252 Paris C?dex 05 -------------- next part -------------- An HTML attachment was scrubbed... URL: http://pwscf.org/pipermail/pw_forum/attachments/20140923/8dfe2205/attachment.html
