If I interpret correctly the question, you are seeing a P = 6.57 kbar and not 7 as in the pw.x input press keyword because, when qe relax the unit cell, it constrains the basis defined with ecutwfc and ecutrho. This basis, as it is formed by plane waves with periodic boundaries, depends on the cell size. So the code will relax reaching 7 kbar (within the accuracy you chose in the input, usually 0.1 kbar), then it will run a new calculation in the final cell recomputing the basis with the new cell. So the value of the pressure will be slightly different.

To be consistent, you should use 6.57 kbar in your plots, as it is the final pressure with the cutoffs you used for your calculation, and does not depend on the starting cell. If you want exactly 7 kbar, you can start a new vc-relax using the final structure you have at 6.57 kbar as starting point, and it will get to a much closer value.

Bests,

Lorenzo

Il 20/09/20 10:54, Stefano Baroni ha scritto:
What is difference between the frequencies computed at: i) P=0; ii) P=6.57 kbar;  iii) 7 kbar? The answer to my question will imply that to yours. SB
Stefano Baroni -  SISSA, Trieste - http://stefano.baroni.me, stefanobaroni (Skype)

If the prediction that an airplane can stay up depends on the difference between Riemann and Lebesgue integration, I don’t want to fly in it [Richard W. Hammings]



On 20 Sep 2020, at 10:42, Mohad Abbasnejad <mohaddeseh.abbasne...@gmail.com <mailto:mohaddeseh.abbasne...@gmail.com>> wrote:

Hello Dear QE users
I am studying the effect of pressure on the frequencies.
In the experimental article, the pressure on the solid has been reported to be 7 kbar.

When I put this pressure (7 kbar) on my structure and let it relax, the final pressure is calculated to be 6.57 kbar as the following. Therefore it is not exactly 7 kbar.

Computing stress (Cartesian axis) and pressure

          total   stress  (Ry/bohr**3)     (kbar)     P=    6.57
   0.00004467   0.00000000  -0.00000000  6.57      0.00     -0.00
   0.00000000   0.00004467  -0.00000000  0.00      6.57     -0.00
  -0.00000000  -0.00000000   0.00004467 -0.00     -0.00      6.57


MY QUESTION: Which pressure should I report on my paper;  7 kbar or 6.57 kbar?


Any comments would be appreciated.

Best regards
Mohaddeseh


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Mohaddeseh Abbasnejad,
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