Thank you All;
aweeks wrote > http://wiki.scilab.org/Tutorials?action=AttachFile&do=view&target=Scilab4Matlab.pdf > page 18 Yes, this document point out the second case nice. Dang, Christophe wrote > The only "right" answer would be a special value, indicating the overflow. Yes, exactly. Dang, Christophe wrote > but int8 represent few values (256), who would waste one value to > implement an error code? Really who? ;) Samuel GOUGEON wrote > If you do the same test for a large matrix, the memory used becomes > asymptotically proportionnal to the matrix size: But how much proportional? According to the link you provided, we reach to the golden formula below to compute the amount the memory used by a Scilab variable: for doubles data type: Number_of_Bytes = Bytes_of_Header + Array_Dim * Bytes_of_theDataType for integer data type: Number_of_Bytes = Bytes_of_Header + Array_Dim * Bytes_of_theDataType + An_Unknown_Amount What do you think of the "An_Unknown_Amount"? Although that document describe doubles, booleans, string, polynomials, ... in detail, we cannot find anything about integer data types. So let me continue with some example: -->Doubles = [ 1 , 2 , 3 ; 4 , 5 , 6 ]; -->whos -name Doubles Name Type Size Bytes Doubles constant 2 by 3 64 -->Number_of_Bytes = (4*4) + (size(Doubles,'*')*8) Number_of_Bytes = 64. -->Integers = int8([ 1 , 2 , 3 ; 4 , 5 , 6 ]); -->whos -name Integers Name Type Size Bytes Integers int8 2 by 3 24 -->Number_of_Bytes = (4*4) + (size(Integers,'*')*1) Number_of_Bytes = 22. Then we have An_Unknown_Amount = 24-22=2 So the question is, What is the "An_Unknown_Amount"? Merci, Mehran _ -- View this message in context: http://mailinglists.scilab.org/Scilab-users-Scilab-and-Matlab-integer-representation-tp4031002p4031007.html Sent from the Scilab users - Mailing Lists Archives mailing list archive at Nabble.com. _______________________________________________ users mailing list [email protected] http://lists.scilab.org/mailman/listinfo/users
