Thanks for reply.

Let me take another example.
The following script fails because x is made as a 1×2×3 hyper matrix and I
can't use 4th and 5th indexes.
In my actual code, the number of 4th and 5th dimensions are variable and I
cant't know in advance.

x=zeros(1,2,3,1,1);
disp(size(x))
a=x(1,1,1,1,1)

Best regards



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