Dear All,
In the help information for the FFT function I find that, regarding the
"inverse" FFT, fft(x,1), the formula is
n
x(k) = SUM(a(m)*exp(2*%i*%pi*(m-1)*(k-1)/n)
m=1
But this is not the inverse FFT since it lacks the required 1/n factor;
however, fft(fft(a,-1),1) indeed returns a. So the procedure seems to be
mistakenly described in the help information.
Interestingly, the fftw3 documentation, http://www.fftw.org/fftw3.pdf,
gives, on page 42, the same formula but it indicates it is an
unnormalized transform.
Would you please clarify?
Regards,
Federico Miyara
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