Hello,
Maybe not optimal, but does the job:
x = [1 1 3
2 1 1
4 5 5];
f = [];
for y=unique(x(:))'
if length(find(x==y)) == 1
f = [f y];
end
end
--> f
f =
2. 3. 4.
S.
Le 05/07/2019 à 18:03, Izabela Wójcik-Grząba a écrit :
Hello,
Is there a simple way of finding elements of matrix which occurs only
once. For example in this matrix it would be 3 and 4:
[1 1 3
2 1 1
4 5 5]
For the time being I couldn't find any smart idea for that. Could you
help?
Kind regards,
Iza
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--
Stéphane Mottelet
Ingénieur de recherche
EA 4297 Transformations Intégrées de la Matière Renouvelable
Département Génie des Procédés Industriels
Sorbonne Universités - Université de Technologie de Compiègne
CS 60319, 60203 Compiègne cedex
Tel : +33(0)344234688
http://www.utc.fr/~mottelet
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