Le 11/02/2020 à 02:37, Federico Miyara a écrit :
Thanks, Samuel.
This certainly clarifies how [] behaves. But is there a rationale for
sum([])==0 and yet cumsum([])==[]?
For sum([])==0 :
IMO this is OK. Personnaly, i expect from
sum(A) + sum(B) + .. sum(Z) not to be killed just because one of the
arguments is []. So, to me, this case is somewhat distinct from the A
+[]. A + [] works element-wise.
Because a vector is expected from sum([],"r"), that then would be added
in an element-wise way,
--> sum([],"r")
ans =
[]
is also OK.
I would give the same rationale for prod([])==1.
By the way, it would be useful to include cumsum and cumprod among the
examples,
Right
Regards
Samuel
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