Hi, I would like to unpack a zip file into a source directory using Maven. What is the best way to do this? Here are the details of what I am trying to do:
- The zip file is essentially the Dojo JavaScript library (ajax-2006.10.10.zip ) - it simply contains JavaScript source. - I would like to unpack this file under my project's ${basedir}/src/main/webapp/scripts. - I don't know if it is ok to keep such artifacts in the maven local repository, but for right now I have kept the Dojo library at .m2/repository/dojo/ajax/2006.10.10/ajax-2006.10.10.zip - I was playing around with the assembly:unpack goal to unpack the library. I tried the following command but it absolutely did not work - obviously I don't know how to use it: mvn assembly:unpack \ -DfinalName=ajax-2006.10.10.zip \ -DoutputDirectory=${basedir}/src/main/webapp/scripts - I would ideally like to have a goal in my pom.xml which will make it easy to perform the unpacking, something like mvn unpack-dojo How can I create something equivalent to this? Thanks for your help. Naresh --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]