Hi, i would like to assemble the following Zip-File from my Maven2 "Jar" Projekt:
myjar-1.0-SNAPSHOT-bin.zip - myjar-1.0-SNAPSHOT.jar (the jar from the POM) - poperties\ - *.properties - lib\ - *.jar (the dependencies from the POM) The Assembly-Descriptor: <?xml version="1.0"?> <assembly> <id>bin</id> <formats> <format>zip</format> </formats> <fileSets> <fileSet> <directory>src/main/external-resources</directory> <outputDirectory>properties</outputDirectory> <includes> <include>**/*.*</include> </includes> </fileSet> </fileSets> <dependencySets> <dependencySet> <outputDirectory>lib</outputDirectory> <unpack>false</unpack> <scope>runtime</scope> </dependencySet> </dependencySets> </assembly> The POM: ... <plugin> <groupId>org.apache.maven.plugins</groupId> <artifactId>maven-assembly-plugin</artifactId> <executions> <execution> <goals> <goal>assembly</goal> </goals> <phase>package</phase> </execution> </executions> <configuration> <descriptors> <descriptor>src/main/assembly/myjar-assembly.xml</descriptor> </descriptors> </configuration> </plugin> ... But the result from "mvn package" is: myjar-1.0-SNAPSHOT-bin.zip - poperties\ - *.properties - lib\ - *.jar (the dependencies) - myjar-1.0-SNAPSHOT.jar (!!!) Is it possible to move the myjar-1.0-SNAPSHOT.jar from the lib\ directory to the toplevel directory of the zip-file? Thank you Volker Brosche _____________________________________________________________________ Der WEB.DE SmartSurfer hilft bis zu 70% Ihrer Onlinekosten zu sparen! http://smartsurfer.web.de/?mc=100071&distributionid=000000000066 --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]