Are you using a Java with Maven project? Assuming so, the process for
what you are asking is a two step one:
1) Ensure the files you wish to access are located under the
src/main/resources folder as shown here:
https://i0.wp.com/www.dineshonjava.com/wp-content/uploads/2016/10/Maven-dirctory-structure.png?w=728&ssl=1
<https://i0.wp.com/www.dineshonjava.com/wp-content/uploads/2016/10/Maven-dirctory-structure.png?w=728&ssl=1>
Doing this should ensure that the file is picked and included in the
compiled jar file.
2) You will need to add to your code. What exactly you add will depend
on whether you are opening the file from a static member or a proper
member function and whether you really need an FileInputStream or just
an InputStream. I have pasted some code to illustrate:
import java.io.File; import java.io.FileInputStream; import
java.io.FileNotFoundException; import java.io.InputStream; import
java.net.URISyntaxException; import java.net.URL; import
java.util.Scanner; /** * * @author parrysg */ public class
ResourceTest { public static void main(String[] args) throws
URISyntaxException, FileNotFoundException { URL url =
ResourceTest.class.getResource("/simpleResource.txt");
FileInputStream fs = new FileInputStream(new File(url.toURI()));
Scanner input = new Scanner(fs);
System.out.println(input.nextLine()); InputStream is =
ResourceTest.class.getResourceAsStream("/simpleResource.txt");
Scanner input2 = new Scanner(fs);
System.out.println(input2.nextLine()); } }
In the above code, I have used main (i.e. a static member), but if you
are opening within a non-static member, it is better to use getClass():
InputStream is = getClass().getResourceAsInputStream();
Note that, if you do just use InputStream, the Exception imports and
throws are not needed; it's overall much simpler.
regards
Stephen Parry
On 23 June 2024 15:50:14 BST, Ulf Zibis <ulf.zi...@cosoco.de> wrote:
Hi, I have a resource file im my project under the folder
"resources". From my code, the file is accessed by: FileInputStream
rs = new FileInputStream(new File("resources/Palm8BitColors.pal"));
This works fine, when I run the application under NetBeans IDE. But
the resource file is not included in the JAR file under "dist", so
it won't run independently of NetBeans. How is the correct way to
integrate and access the file into the JAR? Thanks -Ulf
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