We are getting this exception (ReportingSQLException: Protocol violation).
What does it mean? OpenJPA is openjpa-1.2.1 wiht Oracle Oracle 11.2.0.2.
Caused by: <openjpa-1.2.1-r752877:753278 nonfatal general error>
org.apache.openjpa.persistence.PersistenceException: Protocol violation
{prepstmnt 31390376 SELECT t0.id, t0.bean_type, t0.app_name, t0.app_path,
t0.bundle_id, t0.concurrency, t0.conf, t0.external_id, t0.frequency,
t0.group_name, t0.last_action_number, t0.time_out, t0.time_zone,
t0.user_name, t0.auth_token, t0.created_time, t0.end_time, t0.execution,
t0.job_xml, t0.last_action, t0.last_modified_time, t0.next_matd_time,
t0.orig_job_xml, t0.pause_time, t0.sla_xml, t0.start_time, t0.status,
t0.suspended_time, t0.time_unit FROM COORD_JOBS t0 WHERE (t0.id = ?) AND
t0.bean_type = ? [params=(String) 0008097-101215052506639-oozie-wrkf-C,
(String) CoordinatorJobBean]} [code=17401, state=99999]
...
...
Caused by: org.apache.openjpa.lib.jdbc.ReportingSQLException: Protocol
violation {prepstmnt 31390376 SELECT t0.id, t0.bean_type, t0.app_name,
t0.app_path, t0.bundle_id, t0.concurrency, t0.conf, t0.external_id,
t0.frequency, t0.group_name, t0.last_action_number, t0.time_out,
t0.time_zone, t0.user_name, t0.auth_token, t0.created_time, t0.end_time,
t0.execution, t0.job_xml, t0.last_action, t0.last_modified_time,
t0.next_matd_time, t0.orig_job_xml, t0.pause_time, t0.sla_xml,
t0.start_time, t0.status, t0.suspended_time, t0.time_unit FROM COORD_JOBS t0
WHERE (t0.id = ?) AND t0.bean_type = ? [params=(String)
0008097-101215052506639-oozie-wrkf-C, (String) CoordinatorJobBean]}
[code=17401, state=99999]
--
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