Am 12.05.2010 10:18, schrieb Francesco: > Hi, > in feature.attributes I have an empty object. One more problem is how > could i find the LonLat of the selected feature? > > -------- Messaggio originale -------- > Oggetto: Re: [OpenLayers-Users] Popup over GPX track > Data: Tue, 11 May 2010 13:24:13 -0400 > Mittente: Charles Galpin <cgal...@lhsw.com> > A: Francesco <webfr...@tiscali.it> > > > > Francesco, the feature attributes will be in feature.attributes > (feature.attributes.name etc) > > hth, > charles > > On May 11, 2010, at 12:43 PM, Francesco wrote: > >> Hi, >> I'm trying to display a popup on mouse over GPX track. This is the >> code used to load the track: >> >> var lgpx = new OpenLayers.Layer.Vector("Track", { >> style: {strokeColor: 'red', strokeWidth: 10, >> strokeOpacity: 0.5}, >> projection: map.displayProjection, >> strategies: [new OpenLayers.Strategy.Fixed()], >> protocol: new OpenLayers.Protocol.HTTP({ >> url: 'gpx.php', >> format: new OpenLayers.Format.GPX() >> }) >> }); >> >> map.addLayer(lgpx); >> >> lgpx.events.register('loadend',lgpx,function() { >> var bounds = this.getDataExtent(); >> map.zoomToExtent(bounds); >> }); >> var hoverSelect = new OpenLayers.Control.SelectFeature(lgpx, { >> hover: true, >> onSelect: function(feature) { >> >> --------------> Here I want to display a popup with info from the GPX file >> >> }, >> onUnselect: function(feature) { >> if (feature.popup) { >> map.removePopup(feature.popup); >> feature.popup.destroy(); >> delete feature.popup; >> } >> } >> }); >> map.addControl(hoverSelect); >> hoverSelect.activate(); >> >> I cannot find a way to get the currently selected track segment and >> extract attributes to display inside the popup. >> >> Any idea? >> >> Tnx >> Francesco >> _______________________________________________ >> Users mailing list >> Users@openlayers.org >> http://openlayers.org/mailman/listinfo/users > > > > > _______________________________________________ > Users mailing list > Users@openlayers.org > http://openlayers.org/mailman/listinfo/users
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