Hello all,
If you have something like this:
Statement : On Tuesday, John Smith bought a Honda Accord
(TOP (SBAR (IN On) (S (NP (NNP Tuesday,) (NNP John) (NNP Smith)) (VP (VBD
bought) (NP (DT a) (NNP Honda) (NNP Accord))))))
I have generated that from the Parse class Show() method as bellow:
/**
* Displays this parse using Penn Treebank-style formatting.
*/
public void show() {
StringBuffer sb = new StringBuffer(text.length()*4);
show(sb);
System.out.println(sb);
}
My question is: How can I translate (TOP (SBAR (IN On) (S (NP (NNP
Tuesday,) (NNP John) (NNP Smith)) (VP (VBD bought) (NP (DT a) (NNP Honda)
(NNP Accord)))))) into a tree object?
I think I would parse that with ( -> new node, (-> new child, ) -> end node.
I was thinking on doing something like this, but instead of returning a
string buffer I would return a tree object:
/**
* Appends the specified string buffer with a string representation of
this parse.
*
* @param sb A string buffer into which the parse string can be appended.
*/
public void show(StringBuffer sb) {
int start;
start = span.getStart();
if (!type.equals(AbstractBottomUpParser.TOK_NODE)) {
sb.append("(");
sb.append(type).append(" ");
//System.out.print(label+" ");
//System.out.print(head+" ");
//System.out.print(df.format(prob)+" ");
}
for (Iterator<Parse> i = parts.iterator(); i.hasNext();) {
Parse c = i.next();
Span s = c.span;
if (start < s.getStart()) {
//System.out.println("pre "+start+" "+s.getStart());
sb.append(encodeToken(text.substring(start, s.getStart())));
}
c.show(sb);
start = s.getEnd();
}
if (start < span.getEnd()) {
sb.append(encodeToken(text.substring(start, span.getEnd())));
}
if (!type.equals(AbstractBottomUpParser.TOK_NODE)) {
sb.append(")");
}
}
But is there some example that someone might have already done and you
could refer to me?
Thanks,
Carlos.
