Ok, I'm not a regexp expert but trying out the recommend suggestion
([:space:]?){8} had OOo writer searching and finding all instances
where there was *1* or more consecutive spaces (up to 8).
It found occurances where there was only 4, only 6 etc.... So if this
was used, based on the original question, it would find 8 spaces and
replace with 4, it would then find 1 space and replace with 4... well
at least this is what it did when I tried it.
I may have the wrong end of the stick here, but this is what happened
when I tried it.
Regards,
Paul
On Wed, 26 Jan 2005 09:09:25 -0500, Paul B. <[EMAIL PROTECTED]> wrote:
> David Teague wrote:
> > I have some C++ code with annoyingly many spaces of
> > indentation.
> >
> > I want to replace the leading 8 spaces with 4. If I use eight of the
> > regular expression [:space:]?, as
> >
> > [:space:]?[:space:]?[:space:]?[:space:]?[:space:]?[:space:]?[:space:]?
> >
> > and replace with say four of them, the find button in the find
> > command (Control F) finds every space, not just the 8 space
> > instances.
> >
> > I want only to replace instances of 8 spaces with 4 spaces.
> >
> > How do I do this?
> >
> > (I was just told about the regular expression to match the
> > beginning of a line, so I do know about that.)
> >
> > David Teague
> > Viva Fifths tuning for Double Basses
>
> That seems to work here, but you might try enclosing it in
> parentheses, or better, a more concise nomenclature:
>
> ([:space:]?){8}
>
> Paul
>
> --
> Using OOo m69 on WinXP.
> Given address is infrequently checked. Please reply to group.
>
>
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