On Mon, Feb 01, 2021 at 07:18:24PM +0200, Nir Soffer wrote: > Assuming we could use: > > io_timeout = 10 > renewal_retries = 8 > > The worst case would be: > > 00 sanlock renewal succeeds > 19 storage fails > 20 sanlock try to renew lease 1/7 (timeout=10) > 30 sanlock renewal timeout > 40 sanlock try to renew lease 2/7 (timeout=10) > 50 sanlock renewal timeout > 60 sanlock try to renew lease 3/7 (timeout=10) > 70 sanlock renewal timeout > 80 sanlock try to renew lease 4/7 (timeout=10) > 90 sanlock renewal timeout > 100 sanlock try to renew lease 5/7 (timeout=10) > 110 sanlock renewal timeout > 120 sanlock try to renew lease 6/7 (timeout=10) > 130 sanlock renewal timeout > 139 storage is back > 140 sanlock try to renew lease 7/7 (timeout=10) > 140 sanlock renewal succeeds > > David, what do you think?
I wish I could say, it would require some careful study to know how feasible it is. The timings are intricate and fundamental to correctness of the algorithm. Dave _______________________________________________ Users mailing list -- users@ovirt.org To unsubscribe send an email to users-le...@ovirt.org Privacy Statement: https://www.ovirt.org/privacy-policy.html oVirt Code of Conduct: https://www.ovirt.org/community/about/community-guidelines/ List Archives: https://lists.ovirt.org/archives/list/users@ovirt.org/message/75UVHZEUU6T5AIIYNCK2W37NPHDVH63Z/
