I tried to solve the dispatching of main content with a MainSite component (injection of a 'show' property). But don't know where to get the source from. I know that there is a way to get to the HttpRequest content, but tapestry does encapsulate this and I guess the tapestry way looks different. Generally Url would be something like : http://domain/Index.htm/show/<siteName>.
>From other frameworks I would pass a get parameter and then grap the content by its value (for SEO I would use url-rewrite then). But tapestry goes a different way, so I don't want to workaround tapestry strategy. Here is my Index.htm template: <html xmlns:t="http://tapestry.apache.org/schema/tapestry_5_0_0.xsd";> <head> <title>That is a title</title> </head> <body> <t:MainContent id="show" context="notSure..."/> </body> </html> aldana wrote: > > Hi, I am new to tapestry5. > > Part of webapp should be a tiny CMS. Usually this should be done by a > central FrontController Pattern (analyzing url param like 'site-id' and > then forwarding and displaying the selected content). I read so far that > you should work with actionLinks here. But before implementing an own > InternalLinkReferrerComponent would like to be sure that there isn't > already a standard provided one? > > thanks. > ----- manuel aldana aldana((at))gmx.de software-engineering blog: http://www.aldana-online.de -- View this message in context: http://www.nabble.com/-T5--Existing-InternalLinkReferrerComponent-for-a-CMS--tp20395261p20397624.html Sent from the Tapestry - User mailing list archive at Nabble.com. --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
