Wow! Thanks, that's it. I started without that, but added it when I was
having problems.
Thanks again!
Wendy Smoak wrote:
On 1/8/06, Thom Hehl <[EMAIL PROTECTED]> wrote:
String url = "/visioneer/HomeSearch.jsp";
RequestDispatcher dispatcher =
getServletContext().getRequestDispatcher(url);
dispatcher.forward(request, response);
And I now get this error:
*type* Status report
*message* _/visioneer/HomeSearch.jsp_
In general, you should not be hard-coding the name of the context in your app.
http://tomcat.apache.org/tomcat-5.5-doc/servletapi/javax/servlet/ServletContext.html#getRequestDispatcher(java.lang.String)
"The pathname must begin with a "/" and is interpreted as relative to
the current context root."
So leave off the 'visioneer' part, (which is the context name,) start
with / and then give the path to the resource, depending on where you
moved it to.
HTH,
--
Wendy
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Thom Hehl
Heavyweight Software for Heavyweight Needs
www.heavyweightsoftware.com
--
"In every revolution, there is one man with a vision."--Jerome Bixby
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