Thanks for the sanity check. That did what I expected, so to expand on this, if
I were creating a "real" servlet whose source code opened like this:
package com.kilonovember.Monkey;
import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
public class Monkey extends HttpServlet{
.. programming stuff goes here ...
}
I would create this directory structure under "C:\Apache Software
Foundation\Tomcat 5.5\webapps"?
com/kilonovember
and place my compiled Monkey.class in kilonovember?
Next I would edit the web.xml file and add these elements?
<servlet>
<servlet-name>monkey</servlet-name>
<servlet-class>com.kilonovember.Monkey</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>monkey</servlet-name>
<url-pattern>/monkey</url-pattern>
</servlet-mapping>
Having done that, I would re-start Tomcat and, providing my Monkey.class
compiled correctly, I should expect to be able to type
"http://localhost:8080/monkey"; into my browser's address window and see the
output of Monkey.class. Is that correct?
Thanks to everyone who responded.
--
Charles Knell
[EMAIL PROTECTED] - email
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