I have something that works: in web.xml:
<servlet> <servlet-name>imageServlet</servlet-name> <servlet-class>ImageServlet</servlet-class> <load-on-startup>2</load-on-startup> </servlet> <servlet-mapping> <servlet-name>imageServlet</servlet-name> <url-pattern>/users/image/*</url-pattern> </servlet-mapping> Links to user images are like this: <img src="/starfriend/users/image/${match.thumbName}"> ( I am using Velocity ) and this is the servlet: public class ImageServlet extends HttpServlet { public void doGet(HttpServletRequest req, HttpServletResponse resp) throws IOException { String path = PhotoHandler.getUserImageDirectory(); String pathInfo = req.getPathInfo(); String fileName = path + pathInfo; // Set content type resp.setContentType("jpg"); // Set content size File file = new File(fileName); resp.setContentLength((int) file.length()); resp.setContentType("image/jpeg"); // Open the file and output streams FileInputStream in = new FileInputStream(file); OutputStream out = resp.getOutputStream(); // Copy the contents of the file to the output stream FileCopyUtils.copy(in, out); } } Image directory path is held in a properties file, which is held in memory by a class called PhotoHandler - that is just the way I have it - of course the path to the image folder could be an init parameter of the servlet. --------------------------------------------------------------------- To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]