If you compile the Servlet class and Re-start Tomcat after defining
the mapping in web.xml it should work.

I tried the following and it works:

---------------------------------------------------------------------
web.xml
---------------------------------------------------------------------
   <servlet>
       <servlet-name>login</servlet-name>
       <servlet-class>test66.LoginServlet</servlet-class>
   </servlet>
   <servlet-mapping>
       <servlet-name>login</servlet-name>
       <url-pattern>/servlet/login</url-pattern>
   </servlet-mapping>

----------------------------------------------------------------------
LoginServlet  ---- compiled
----------------------------------------------------------------------
package test66;

import javax.servlet.*;

public class LoginServlet extends HttpServlet {
   public void doPost(HttpServletRequest request, HttpServletResponse
response){
       doGet(request,response);
   }

   public void doGet(HttpServletRequest request, HttpServletResponse response){
       System.out.println(" Inside Login Servlet");
   }
}

------------------------------------------------------------------------------------
JSP
------------------------------------------------------------------------------------
<%@ page contentType="text/html;charset=UTF-8" language="java" %>
<html>
 <head><title></title></head>
 <body>
 <FORM action="<%=request.getContextPath()%>/servlet/login" method="POST" >
     <input type="text" name="text" value="hellooooo "/>
     <input type="submit" name="submit" value="submit" />
 </FORM>
 </body>
</html>

-Rashmi

On 4/5/07, jacky <[EMAIL PROTECTED]> wrote:
It is <webapp>/servlet/login indeed. In fact, my jsp structure is as
following:
in index.jsp:
  <jsp:include page="/jsp/top.jsp"/>

in top.jsp:
<FORM action="<%=request.getContextPath()%>/servlet/login" method="POST"
onsubmit="return loginCheck(this);">
..
</FORM>
//here, the form will be submit



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