If you compile the Servlet class and Re-start Tomcat after defining
the mapping in web.xml it should work.
I tried the following and it works:
---------------------------------------------------------------------
web.xml
---------------------------------------------------------------------
<servlet>
<servlet-name>login</servlet-name>
<servlet-class>test66.LoginServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>login</servlet-name>
<url-pattern>/servlet/login</url-pattern>
</servlet-mapping>
----------------------------------------------------------------------
LoginServlet ---- compiled
----------------------------------------------------------------------
package test66;
import javax.servlet.*;
public class LoginServlet extends HttpServlet {
public void doPost(HttpServletRequest request, HttpServletResponse
response){
doGet(request,response);
}
public void doGet(HttpServletRequest request, HttpServletResponse response){
System.out.println(" Inside Login Servlet");
}
}
------------------------------------------------------------------------------------
JSP
------------------------------------------------------------------------------------
<%@ page contentType="text/html;charset=UTF-8" language="java" %>
<html>
<head><title></title></head>
<body>
<FORM action="<%=request.getContextPath()%>/servlet/login" method="POST" >
<input type="text" name="text" value="hellooooo "/>
<input type="submit" name="submit" value="submit" />
</FORM>
</body>
</html>
-Rashmi
On 4/5/07, jacky <[EMAIL PROTECTED]> wrote:
It is <webapp>/servlet/login indeed. In fact, my jsp structure is as
following:
in index.jsp:
<jsp:include page="/jsp/top.jsp"/>
in top.jsp:
<FORM action="<%=request.getContextPath()%>/servlet/login" method="POST"
onsubmit="return loginCheck(this);">
..
</FORM>
//here, the form will be submit
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