Greetings,
Specifics: Window XP TomCat 5.5 Java 1.6 Created webapp dirs under; C:\Program Files\Apache Software Foundation\Tomcat 5.5\webapps\ Called ch1\WEB-INF\classes In WEB-INF at created a web.xml file with the following contents; <?xml version="1.0" encoding="ISO-8851-1" ?> <web-app xmlns="http://java.sun.com/xml/ns/j2ee"; xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"; xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"; version="2.4"> <servlet> <servlet-name>Chapter1 Servlet</servlet-name> <servlet-class>Ch1Servlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>Chapter1 Servlet</servlet-name> <url-pattern>/Serv1</url-pattern> </servlet-mapping> </web-app> In the classes subdir to WEB-INF I compile the following java src successfully import javax.servlet.*; import javax.servlet.http.*; import java.io.*; public class Ch1Servlet extends HttpServlet { public void doGet(HttpServletRequest request, HttpServletResponse response) throws IOException { PrintWriter out = response.getWriter(); java.util.Date today = new java.util.Date(); out.println("<html> " + "<body>" + "<h1 align=center>HF\'s Chapter1 Server</h1>" + "<br>" + today + "</body>" + "</html>"); } } I installed TomCat 5.5 as a windows server and can successfully launch http://localhost:8080 <http://localhost:8080/> and get the TomCat initial page Under this page I can select the link for TomCat manager and see under applications an entry for /ch1 However, when I try to run <http://localhost:8080/ch1/Serv1> http://localhost:8080/ch1/Serv1 I get HTTP Status 404 - /ch1/Serv1 Anyone want to help a newbie?
