I installed the .exe file http://tomcat.apache.org/download-55.cgi ---> Binary Distribution --> Core -- > Windows Service Installer<http://datadispensary.com/apache/tomcat/tomcat-5/v5.5.27/bin/apache-tomcat-5.5.27.exe>( pgp<http://www.apache.org/dist/tomcat/tomcat-5/v5.5.27/bin/apache-tomcat-5.5.27.exe.asc>, md5<http://www.apache.org/dist/tomcat/tomcat-5/v5.5.27/bin/apache-tomcat-5.5.27.exe.md5> )
I just double click on the .exe and followed the instructions. In my environment variables I set the java path as PATH = jdk1.5 On Tue, Mar 17, 2009 at 3:17 AM, André Warnier <a...@ice-sa.com> wrote: > Dharani wrote: > >> I installed apache-tomcat-5.5.27.exe in windows platform (In the machine I >> have installed jdk1.6. ) >> > > When you downloaded Tomcat, there was a choice between 2 versions : > - an msi installer > - a zip file > > Which one did you download and install ? > > But the server doesn't start with Windows start. Always I have to go to >> binfolder and run tomcat5.exe to start the server. >> >> How can I configure the server to start with when Windows starts? >> > First answer the above question, then we'll know better what to tell you. > > >> Is the problem occurring because of I use jdk1.6? >> > No. > > > > --------------------------------------------------------------------- > To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org > For additional commands, e-mail: users-h...@tomcat.apache.org > >
