Jonathan Mast wrote:
How do I specify wildcards in the RemoteAddrValue declaration?
The Tomcat docs says it uses the java.util.regex package, so i wrote a test
case like this:
String patternStr = "192.168.*.*";
String searchStr = "192.168.1.2";
Pattern p = Pattern.compile(patternStr);
Matcher m = p.matcher(searchStr);
System.out.println("Does " + patternStr);
System.out.println("Match " + searchStr);
boolean b = m.matches();
System.out.println("Result: " + b);
Which returns true, however when I placed patternStr into my server.xml file
(following the conventions in the Tomcat docs of escaping the "." with \ ):
<Valve className="org.apache.catalina.valves.RemoteAddrValve"
allow="192\.168\.*\.*"/>
This is not a "Tomcat convention", it is how regular expressions work.
In a regular expression,
a "." means 'any character'
"\." mean 'the character "."'
the expression "\.*" means "a ".", 0 or n times"
The expression "192.168.1.2", as a regexp, matches "192.168.1.2", but
also matches "192A168+1C2" and "19201689152" (and a lot more strings),
since an unescaped "." matches any character.
The regexp "192.168.*.*" does not make much sense, since the first ".*"
will match anything that follows (or nothing), leaving nothing to match
for the second ".*".
To match any address starting with "192.168.", use
<Valve className="org.apache.catalina.valves.RemoteAddrValve"
allow="192\.168\..*"/>
or (if you want to be really finicky about it)
<Valve className="org.apache.catalina.valves.RemoteAddrValve"
allow="192\.168\.\d{1,3}\.\d{1,3}"/>
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