Basically, what I am sending to the server is a byte array that is a picture
taken from a cell-phone camera. My client-side code looks like this:
url = new URL(urlString);
connection = (HttpURLConnection) url.openConnection();
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setUseCaches(false);
connection.setRequestMethod("POST");
dos = new
DataOutputStream(connection.getOutputStream());
dos.write(Global.rawImage);
dos.close();
Now what I need the server to do, is to write this image to a file in the
directory /webapps/geosim/DRimages/. Here is what I have:
doPost:
try {
DataInputStream is = new
DataInputStream(request.getInputStream());
raw = new byte[800000];
for(i=0; i<800000; i++)
raw[i] = '\0';
i = 0;
len = 0;
while((i = is.read(raw)) != -1) {
}
file = new File(filePath + d.getTime() + ".jpg");
fos = new FileOutputStream(file);
fos.write(raw);
fos.close();
file = new File("../webapps/geosim/gen-html/DR.html");
fos = new FileOutputStream(file, true);
tag += new String(" \"./DRimages/" " + d.toString() +
"::::" + coordsStr
+ "</img><br>\n");
fos.write(tag.getBytes());
fos.close();
You can ignore the coordsStr for now, that will be null until I find a way
of dealing with embedding the lat/long in the digital image. Basically I
just want to write the image to the server-side directory
TOMCAT_HOME/webapps/geosim/DRimages/
Could you guys help show me how to do this using the ServletContext resource
handling? I'm unfamiliar with how to do this.
mgainty wrote:
>
>
> post the code and we'll walk you thru it
>
> no sweat
> Martin
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>> Date: Thu, 28 May 2009 14:51:28 -0700
>> From: [email protected]
>> To: [email protected]
>> Subject: RE: Debian Tomcat Fail
>>
>>
>> Sorry, this code was provided to me by a graduate student (I'm a lowly
>> freshman). Still very new to all of this, I'll look into that.
>>
>>
>> Caldarale, Charles R wrote:
>> >
>> >> From: trojansnake12 [mailto:[email protected]]
>> >> Subject: RE: Debian Tomcat Fail
>> >>
>> >> File myGifImage = new
>> File("../webapps/geosim/WEB-INF/images/test.jpg");
>> >
>> > Very bad form. The servlet container (Tomcat) is under no obligation
>> to
>> > provide *any* access to the underlying file system (if there is one),
>> > other than to a scratch area. You should be using
>> > ServletContext.getResourceAsStream() rather than expecting File objects
>> to
>> > work.
>> >
>> > - Chuck
>> >
>> >
>> > THIS COMMUNICATION MAY CONTAIN CONFIDENTIAL AND/OR OTHERWISE
>> PROPRIETARY
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>> > received this in error, please contact the sender and delete the e-mail
>> > and its attachments from all computers.
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