Hi.
I do not really understand the issue here.
If you are under Windows, with Tomcat running as a Service, then you can just run the
commands "net start tomcat6" / "net stop tomcat6" to start/stop tomcat.
If you are under Linux, then you can just issue the command "/etc/init.d/tomcat6
(start|stop)".
Under most Unixes, the procedure is similar.
So where is the problem ?
Rob Gregory wrote:
I call the scripts via code to both stop and start Tomcat. There is a
problem with even calling these scripts via Unix unless you change (cd)
into the bin directory before running startup.sh as the log paths are
generated relative to the startup.sh location.
String strCatalinaBin = System.getenv("CATALINA_HOME") +
"\\bin\\";
File objDir = new File(strCatalinaBin);
r = Runtime.getRuntime();
p = r.exec(new String[] { "cmd.exe", "/C", "start",
strCatalinaBin + "catalina.bat", "start" }, null, objDir);
p.waitFor();
p.destroy();
Hope this helps.
Rob
-----Original Message-----
From: Karthik Nanjangude [mailto:karthik.nanjang...@xius-bcgi.com]
Sent: 11 October 2010 13:26
To: Tomcat Users List
Subject: RE: Starting/Stopping Tomcat from Java program
Hi
Probably u may need to use Embedded version of TOMCAT to do this
activity...
With regards
karthik
-----Original Message-----
From: kshitij chandrasen [mailto:kshtjchnd...@gmail.com]
Sent: Monday, October 11, 2010 2:49 PM
To: users@tomcat.apache.org
Subject: Starting/Stopping Tomcat from Java program
Hi,
I've to write methods on calling which i'd be able to start and stop
the
tomcat app server. I tried this -
I'm using Tomcat 6.0.26.
String[] command = new String[4];
command[0] = "cmd";
command[1] = "/C";
command[2] = "startup.bat";
command[3] = "C:\\";
String x[] = {"PATH=C:\\Program Files\\Apache Software
Foundation\\Apache
Tomcat 6.0.26\\bin","CATALINA_HOME=C:\\Program Files\\Apache Software
Foundation\\Apache Tomcat 6.0.26","JAVA_HOME=C:\\Program
Files\\Java\\jdk1.6.0_21","JRE_HOME=C:\\Program Files\\Java\\jre6"};
Process p = Runtime.getRuntime().exec(command,x);
This gives me a strange windows error saying - The system cannot
find the
file -Djava.util.logging.config.file="C:\Program Files\Apache Software
Foundation\Apache Tomcat 6.0.26\conf\logging.properties", while it
actually
exists.
If instead of setting the path, I give the absolute path of
startup.bat in
command[3], it works fine -
Process p = Runtime.getRuntime().exec("cmd /C start
C:\\broadway\\bat\\startup.bat"); //I copied the startup.bat to a
folder and
ran it from there, it worked fine.
Please give me pointers to the right direction!
--
Kshitij Chandrasen
Engineer, Software Engineering,
Cisco Systems, CBSBU Engineering.
--
Kshitij Chandrasen
Engineer, Software Engineering,
Cisco Systems, CBSBU Engineering.
---------------------------------------------------------------------
To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org
For additional commands, e-mail: users-h...@tomcat.apache.org
---------------------------------------------------------------------
To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org
For additional commands, e-mail: users-h...@tomcat.apache.org
---------------------------------------------------------------------
To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org
For additional commands, e-mail: users-h...@tomcat.apache.org
