I need to set up the environment variable JAVA_HOME and and
CATALINA_HOME to start some web and Java EE, am little bit confused
with conflicting information.
When I run
java -version
ie get
java version "1.6.0_18"
OpenJDK Runtime Environment (IcedTea6 1.8.2)
(fedora-43.1.8.2.fc13-x86_64)
OpenJDK 64-Bit Server VM (build 14.0-b16, mixed mode)
When I run "which java"
I get
"/usr/bin/java[/QUOTE]"
checking my usr/share I see several directories
java (full of files and directories)
java-1.3.0 (1 jar in it)
java-1.3.1 (empty)
java-1.4.0 (empty)
java-1.5.0 (empty)
java-1.6.0 (empty)
java-1.7.0 (empty)
Issuing the "echo %PATH gives the following"
/usr/lib64/qt-3.3/bin:/usr/kerberos/sbin:/usr/kerberos/bin:/usr/lib64/ccache:/usr/local/bin:/usr/bin:/bin:/usr/local/sbin:/usr/sbin:/sbin:/home/salam/bin
In eclipse helios 3.6, I see in preferences > Java I have
/usr/lib/jvm/java-1.6.0-openjdk-1.6.0.0.x86_64
How one can check that he has Java EE setup correctly with Apache Tomcat
6 ?
I have Apache Tomcat up and running and need to setup CATALINA_HOME.
In the usr/share/java directory, I have a directory "tomcat6" as well as
a tomcat6 directory in /usr/share/. In Eclipse, when I try to add a
server, eclipse doesnt see that I have a type of tomcat server.
I have found so many articles on the web but no 2 articles are similar.
I tried to browse Sun's "Path setup tutorial" but it seems it is not
available anymore.
Thanks for your help
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