hi tomee 1 is jaxrs 1.0, clientBuilder API is jaxrs 2. You can use tomee 7
Romain Manni-Bucau @rmannibucau <https://twitter.com/rmannibucau> | Blog <https://blog-rmannibucau.rhcloud.com> | Old Blog <http://rmannibucau.wordpress.com> | Github <https://github.com/rmannibucau> | LinkedIn <https://www.linkedin.com/in/rmannibucau> | JavaEE Factory <https://javaeefactory-rmannibucau.rhcloud.com> 2016-12-07 17:18 GMT+01:00 José Luis Cetina <maxtorz...@gmail.com>: > Hi. Currently im using TomEE 1.7.4 JAXRS. > > In my project we currently use our own services for receiving request to > our server. We use @Path, @Post .... etc. This works great. > > No i want create an HTTP Request in my java class to an external API. I see > an example like this: > > Client client = ClientBuilder.newClient(); > String target = "...."; > Response responseTwilio = client.target(target) > .request(MediaType.APPLICATION_JSON_TYPE) > .get(); > > When i try to use it i always get an ClassNotFoundException for > ClientBiulder... why this happen? > > Why i can get request but why i cannot create a request for send to another > server? I know TomEE use CXF, do i have to add any CXF dependency? > > extract of my pom: > > <dependency> > <groupId>javax</groupId> > <artifactId>javaee-api</artifactId> > <version>${javaee.version}</version> > <scope>provided</scope> > </dependency> > > > <dependency> > <groupId>com.fasterxml.jackson.jaxrs</groupId> > <artifactId>jackson-jaxrs-json-provider</artifactId> > <version>${jackson.provider.version}</version> > <scope>compile</scope> > </dependency> > > ..... > > > Thanks. > > > > -- > ------------------------------------------------------------------- > *José Luis Cetina* > ------------------------------------------------------------------- >
