This is not really related to wicket, since your properties file is
available in your classpath, you should be able to get it as a resource.
Something like:
Properties props=new Properties () ;
props.load (
getClass().getResourceAsStream("/WEB-INF/conf/database.properties") ) ;
If you're in a static method of class initializer, you'll need to refer to
the class using MyClass.class before the getResourceAsStream(). Note that
you can actually use any Class object, since the path to the resource is
absolute (starting with a slash).
HTH,
Xavier
On 9/1/07, Edi <[EMAIL PROTECTED]> wrote:
>
>
> Hello,
>
> I have one sample project named as TMS, In my "WEB-INF/conf" foler
> contains
> database.properties file. It contains
>
> e.g
> hostname = some host name
> url= some url
>
> This project contains only one database.properties file.
> In java file, I want to get hostname and url from that property file.
>
> e.g.
>
> Properties props=new Properties () ;
> props.load ( new FileInputStream ( new File
> ("E:\\Workspace\\TMS\\WebRoot\\WEB-INF\\conf\\database.properties"))) ;
>
> String host= "hostname";
> String val = props.getProperty ("Host Name Is :"+ host ) ;
>
> Using the above code, I have got both hostname and url.
>
> But my problem is, How to get the current project database.properties file
> path.
>
> Because in the above path name is hard coded.
>
> So How we get current project database.properties file path?
>
> Thanking you.
>
> --------------------
>
> Thank You
> Edward
> --
> View this message in context:
> http://www.nabble.com/How-to-get-path-name--tf4363832.html#a12438194
> Sent from the Wicket - User mailing list archive at Nabble.com.
>
>
> ---------------------------------------------------------------------
> To unsubscribe, e-mail: [EMAIL PROTECTED]
> For additional commands, e-mail: [EMAIL PROTECTED]
>
>
--
Xavier Hanin - Independent Java Consultant
http://xhab.blogspot.com/
http://incubator.apache.org/ivy/
http://www.xoocode.org/
