Hello again, I have a form with ajax validation on its component's 'onblur' and a sumit link. The submission process takes a while as it results in numerous database lookups and so on. Initially I used an IndicatingAjaxSubmitButton to show the user that their request was being processed, with the help of mailinglist and #wicket members I also disabled the link during the submission with an AjaxCallDecorator and I suppose I could always add a modal div over the whole site as well (in the same callDecorator) in order to stop users changing the form contents or navigating to another part of the site.
That all works fine however I need to push this further. If a user submits information which corresponds to a object that already exists in the database, I need to ask him whether he wishes to create a duplicate. The way I see this working is as follows. The user submits a valid form by clicking the link. This results in a modal centered dialog with some loading animation being displayed. If the submission works the user is redirected to a 'success' page where the entered data is display along with any information calculated during the submission. However if there is an error (an Exception thrown from the server) either a connection problem or duplicate data, the animation is replaced by some text explaining the problem and 1 or 2 buttons (Cancel for connection problems and Make Duplicate/Cancel for duplicate data). The Cancel button simply removes the modal window effectively returning the user to the form, whereas the Duplicate button launches the submission again and displays the animation until it succeeds or fails again in the case of connectivity problems. I know this a lot to ask but has anyone got any idea how to achieve this as I'm getting a tad confused! Many Thanks Anthony
