great!
i didn't think it was THAT easy.
i spend a whole day to find an answer to this, but was looking at the wrong
places.
thank you
-------- Original-Nachricht --------
> Datum: Thu, 27 Nov 2008 11:06:31 -0500
> Von: Michael O\'Cleirigh <[EMAIL PROTECTED]>
> An: users@wicket.apache.org
> Betreff: Re: getting ip address from URIRequestTargetUrlCodingStrategy
> Hi Stefan,
>
> You can get the IP address that sent the request like this:
>
> WebRequest wr = (WebRequest) RequestCycle.get().getRequest();
>
> String originatingIPAddress = wr.getHttpServletRequest().getRemoteHost();
>
> You can probably place it directly in the decode(...) method of your url
> coding strategy.
>
> Regards,
>
> Mike
>
> > in my webapp i want to serve files from the filesystem to the user. so i
> coded something like this:
> >
> > mount(new URIRequestTargetUrlCodingStrategy("/files") {
> > @Override
> > public IRequestTarget decode(RequestParameters
> requestParameters) {
> >
> > final String fileId = getURI(requestParameters);
> >
> > ... read some info from database and build a fileInfo object ...
> >
> > /* Get file for this instance */
> > return new ResourceStreamRequestTarget(new
> AnonFileResourceStream(fileInfo));
> > }
> > });
> >
> > (AnonFileResourceStream extends AbstractResourceStream)
> >
> > all requests to "/files" use the remaining part of the request to ask
> the database where the real file is located and stream it to the client.
> > the problem is that i need to know from which ip address the request was
> made. i need the WebRequest object for this request to get some http
> headers.
> > is this possible or is there another way to get hold of this
> information?
> >
> >
> > thanx alot
> > stefan
> >
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> >
>
>
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