Hi, I have created a BookmarkablePageLink and I would like to grab a properly escaped URL-string which I can then send through e-mail.
For my first try noHtmlSensitiveChars & fullyEscaped contained the empty ("") string: PageParameters pars = new PageParameters(); pars.add("confirmationCode", "someconfcodestring"); BookmarkablePageLink bookmarkablePageLink = new BookmarkablePageLink("link", ForgotPasswordRequest.class, pars); String noHtmlSensitiveChars = bookmarkablePageLink.getModelObjectAsString(); String fullyEscaped = Strings.escapeMarkup(noHtmlSensitiveChars, true, true).toString(); System.out.println("No sensitive chars:" + noHtmlSensitiveChars); System.out.println("Fully escaped:" + fullyEscaped); Any ideas on how I could solve this? Best regards, Kent --------------------------------------------------------------------- To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org