chain the two models:
class numstringmodel extends abstractreadonlymodel<string> {
private final imodel<integer> intmodel;
public numstringmodel(imodel<integer> intmodel) { this.intmodel=intmodel; }
public string getobject() {
int val=intmodel.getobject();
switch (val) ....
}
public void detach() {
intmodel.detach();
}
}
add(new label(.., new numstringmodel(new propertymodel(...
-igor
On Tue, Nov 17, 2009 at 9:11 PM, smallufo <[email protected]> wrote:
> Hi all
>
> I've already converted most of my code from 1.3 to 1.4 , except this
> situation :
>
> Label intToStringLabel = new Label("intToString" , new
> PropertyModel(this , "integer")
> {
> �...@override
> public Object getObject()
> {
> int value = ((Integer) super.getObject()).intValue();
>
> switch(value)
> {
> case 1: return "one";
> case 2: return "two";
> case 3: return "three";
> }
> return "";
> }
> });
> add(intToStringLabel);
>
> In the code , I want to output Integer of 1,2,3 to "one" , "two" and
> "three"
>
> In the code , PropertyModel is not parameterized , so I change to :
> new PropertyModel<Integer>(this , "integer")
> and eclipse warns getObject() 's return type should be Integer
> But what I want to return is String , not Integer . This doesn't work.
>
> OK , then , I change my code to
> new PropertyModel<String>(this , "integer")
>
> and eclipse warns
> ((Integer) super.getObject()).intValue();
> Cannot cast from String to Integer.
>
> I don't know what else can I do , How to parameterize this situation ?
>
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