Hi,
'Ajax POST stopped because of precondition check' is probably your
problem. all wicket ajax can have a precondition, which is basically
a function that returns true or false, and will only execute the ajax
if it returns true. I expect that for some reason in your case this
function is returning false.
for an AjaxButton (well AjaxFormSubmitBehavior) the precondition is
this: "return Wicket.$$(this)&&Wicket.$$('" + getForm().getMarkupId()
+ "')";
in the wicket ajax javascript file i see this:
// returns if the element belongs to current document
// if the argument is not element, function returns true
Wicket.$$ = function(element) {
.......
}
This must be failing for you, which I presume has something to do with
how you are passing the content into the qtip;
content: $('#" + contentMarkupId + "').html()
Hope that helps.
--
Regards - Richard Wilkinson
Developer,
jWeekend: OO & Java Technologies - Development and Training
http://jWeekend.com
On 9 March 2010 13:05, Antoine van Wel <antoine.van....@gmail.com> wrote:
> Hi everybody,
>
> Integrating a Jquery tooltip (qtip) went smoothly until I tried to do
> an Ajax form submit.
> The Wicket Ajax Debug panel shows an "Ajax POST stopped because of
> precondition check", so an Ajax response is never sent.
>
> What I'm doing is simply render the text for the tooltip on the same
> page in a hidden div, then pointing the content of the tooltip to that
> div.
>
> the html:
>
> <wicket:head>
> <script type="text/javascript" src="/js/jquery-1.3.2.min.js"></script>
> <script type="text/javascript"
> src="/js/jquery.qtip-1.0.0-rc3.min.js"></script>
> </wicket:head>
>
> <wicket:extend>
> <div wicket:id="content" style="display: none;">
> <form wicket:id="form">
> <input type="submit" wicket:id="clickme" value="click
> me">
> </form>
> </div>
>
> <span wicket:id="tipme">hover over me</span>
> </wicket:extend>
>
> the page class:
>
> public class JQueryTestPage extends BasePage {
> public JQueryTestPage() {
> WebMarkupContainer content = new WebMarkupContainer("content");
> add(content);
>
> Form<Void> form = new Form<Void>("form");
> content.add(form);
> form.add(new AjaxButton("clickme") {
> �...@override
> protected void onSubmit(AjaxRequestTarget target,
> Form<?> form) {
> System.out.println("testing");
> }
>
> });
>
> WebMarkupContainer qtip = new WebMarkupContainer("tipme");
> add(qtip);
> qtip.add(new QTipBehavior(qtip, content));
> }
>
> }
>
>
> and finally the QTipBehavior:
>
> public class QTipBehavior extends AbstractBehavior {
> private String componentMarkupId;
> private String contentMarkupId;
>
> public QTipBehavior(Component parent, Component content) {
> contentMarkupId = content.getMarkupId();
> componentMarkupId = parent.getMarkupId();
> }
>
> �...@override
> public void renderHead(IHeaderResponse response) {
> String javascript = new StringBuilder()
> .append("$(function() {")
> .append(" $('#" + componentMarkupId +
> "').qtip({")
> .append(" content: $('#" +
> contentMarkupId + "').html(),")
> .append(" hide: { fixed: true },")
> .append(" position: { corner: { target:
> 'topRight', tooltip:
> 'leftTop' } },")
> .append(" })")
> .append("});")
> .toString();
> response.renderOnDomReadyJavascript(javascript);
> }
> }
>
>
> All pretty straightforward.
>
> So my guess is somehow Wicket is not happy about the redirection I
> created by not using the rendered button directly.
> I've been trying to debug this using Firebug, obviously without success.
>
> Does anybody have any hints how to solve this? Is the approach I'm
> taking flawed? Maybe jWicket or wiQuery could help here?
>
>
>
> Antoine
>
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