I initially tried etResponsePage(SSISignOutPage.class) it did not worked , so used the new approach ,
regarding what my SSISignOutPage it does nothing except for showing a link , before to that the control never goes to the page constructor , I am assuming after a session is invalidated wicket removes all its pages from page map and its possible that it cannot find the page SSISignOutPage and for that reason do I get pageExpired error ? christian.giambalvo wrote: > > Depends on what your SSISignOutPage.class does. > But why don't use setResponsePage(SSISignOutPage.class) ?? > > -----Ursprüngliche Nachricht----- > Von: tubin gen [mailto:fachh...@gmail.com] > Gesendet: Donnerstag, 25. März 2010 12:59 > An: users > Betreff: signout and redirect > > here is my code to signout link. > > add(new Link<Void>("signout"){ > @Override > public void onClick() { > ((AuditWebSession)(Session.get())).signout(); > throw new RestartResponseException(SSISignOutPage.class); > } > }); > > when user clicks on signout I expect to go to SSISignOutPage. > but I end up with a different page which is set in applicationsettings > > IApplicationSettings settings= super.getApplicationSettings(); > settings.setPageExpiredErrorPage(SessionExpiredPage.class); > > > the SessionExpiredPage . > please tell me what could be causing this ? > > --------------------------------------------------------------------- > To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org > For additional commands, e-mail: users-h...@wicket.apache.org > > > -- View this message in context: http://old.nabble.com/signout-and-redirect-tp28027857p28029507.html Sent from the Wicket - User mailing list archive at Nabble.com. --------------------------------------------------------------------- To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
