simply disabling the link, calling setenabled(false), will get you there. also see link#setbefore/afterdisabledlink(string markup) which looks like you may want to set to ""
-igor On Tue, Jun 8, 2010 at 12:37 PM, Fernando Wermus <fernando.wer...@gmail.com> wrote: > Hi all, > I have a menu that it structure is the following: > > > 1. for the link selected > > <ul id="someId"> > <li> > <em> selected item </em> > </li> > .... > > > 2. for the link not selected > > <ul id="someId"> > <li> > <em> > <a> item not selected</a> > <em> > </li> > ... > > > I programmed this with a border that renders the <em>, but I need make > invisible the border, but not the anchor to get the first case. > > I tried: > > border.setVisible(false); > border.getBodyContainer().setVisible(true); > > and I got an error: > > at java.util.AbstractList$Itr.remove( > AbstractList.java:356) > at org.apache.wicket.Page.checkRendering(Page.java:1139) > at org.apache.wicket.Page.renderPage(Page.java:921) > at > org.apache.wicket.request.target.component.BookmarkablePageRequestTarget.respond(BookmarkablePageRequestTarget.java:240) > > > Which is the best way to achieve this? > > I supposed that if a decorator didn't render it would mean the body would > still be rendered - it is a decorator, not a classic container. > > thanks in advance > > > -- > Fernando Wermus. > > www.linkedin.com/in/fernandowermus > --------------------------------------------------------------------- To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
