hi all,
I have form with two submit buttons & want different behavior for each
button.

submitButton:
- standard submit button
- expected "onClick" behavior: validate form & save the form's model
(implemented in form's onSubmit() method) & redirect to another page

ajaxButton:
- AjaxButton
- expected "onClick" behavior: validate form, if valid get form's model
& display it as XML in modal window for preview

the problem is that form's onSubmit() is called when I click on
ajaxButton - I need to keep validation but do not call form's onSubmit()
method, i.e. stay on the current form page & do not save the model.
Is there any chance to do this wicket way?

thanks,
marek


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