Ernesto Reinaldo Barreiro-4 wrote:
> 
> Yes you are right... but I think new PropertyModel(this,
> "selectedEintrag.vorname") will work I guess.
> 

I guess you are right. That will work, but it is not very elegant to put a
reference to the page or panel into the model. He probably should not
overwrite the reference on "selectedEintrag" or use the readonly model you
suggested.

I think I would put a new Model() into the label and then, instead of
overwriting the variable "selectedEintrag", call
label.setModelObject(item.getModelObject().getVorname())


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Regards, 
Hans 

http://cantaa.de 

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