Thank you all for replying
It does sound like I'm trying to do something impossible, but I would like
to post my code here in case i did not explain the problem correctly:
I add onbeforeunload event to the body of my page, which calls a JS
function. The JS does submit to my form. In my form onSubmit() I do a
setResponsePage.
I see that it get's into the onSubmit() (and even to the destination page's
constructor), but after exit from onSubmit(), it returns to the original
page (refereshing the entered data).
Here's the code:
on page
--------
body.add(new SimpleAttributeModifier("onload", "isSubmit=false;"));
StringBuilder js = new StringBuilder();
js.append("if(!isSubmit){checkLeaving( '");
js.append(getString("leaveWizardMessage"));
js.append("', '");
js.append(newAccountWizard.getForm().getMarkupId());
js.append("', '");
js.append(newAccountWizard.getConfirmationModal().getMarkupId());
js.append("')};");
body.add(new SimpleAttributeModifier("onbeforeunload", js.toString()));
add(body);
js file
--------
function checkLeaving(message, formId, modalId, linkId){
//alert("formId = " + formId);
var answer = confirm(message);
if(answer == true){
var form = document.getElementById(formId);
//var modal = document.getElementById(modalId);
//var submitLink = document.getElementById(linkId);
alert("before submit");
form.submit();
//submitLink.onclick();
//return false;
}
}
wizard panel
-------------
@Override
protected Form newForm(String id) {
form = new Form(id){
@Override
protected void onSubmit() {
System.out.println("in form submit1");
setResponsePage(NewAccountRegistrationPage.class);
System.out.println("in form submit2");
}
protected void onError() {
System.out.println("in form error");
};
};
Can someone please tell me if it's possible?
Rebbaca
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