I am not familiar with wicket.. please help to give me suggestion for How
to implement this?
1. click a button and show a confirm message.
2. suspend 1 minute
3. submit the form..
public ActivityAjaxButton(final ButtonForm form, SessionBean
sessionBean, String id, int seqRequest, String rootSrc) {
super(id, form);
this.form = form;
this.seqRequest = seqRequest;
this.rootSrc = rootSrc;
this.setModel(new Model(sessionBean));
add(new AjaxFormSubmitBehavior(form, "onclick") {
private static final long serialVersionUID = 1L;
protected void onSubmit(AjaxRequestTarget target){
target.appendJavascript("alert('Sumibt
Successfully')");
ActivityAjaxButton.this.onSubmit(target, form);
}
protected void onError(AjaxRequestTarget target){
ActivityAjaxButton.this.onError(target, form);
}
protected CharSequence getEventHandler(){
return new AppendingStringBuffer
(super.getEventHandler()).append("; return false;");
}
protected IAjaxCallDecorator getAjaxCallDecorator()
{
return
ActivityAjaxButton.this.getAjaxCallDecorator
();
}
public CharSequence getCallbackUrl(){
return Utils.generateUrl(this, null,
getComponent
(), useRelativeUrls);
}
}.setThrottleDelay(Duration..ONE_MINUTE));
.........
protected void onSubmit(AjaxRequestTarget target, Form form) {
SessionBean sessionBean = (SessionBean)getModelObject();
modelChanging();
doNavigate(sessionBean, seqRequest, target);
modelChanged();
}
........
}
Best Regards,
Joan Wang
Best Regards,
BSID/ERP
Joan Wang 王琇緯
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