If this really ist he HTML code that you use, you should terminate your <input> tages with /> <div align="center"> <input type="submit" wicket:id="back" /> <input type="submit" wicket:id="display" onclick="target='_blank';return true;"/> </div>
Have you checked (yuse debug tool of your browser) waht html code is used by your browser? Sometimes (e.g. chrome) browsers are quite smart and they re-arrange html code when somehtin is wrong. Stefan -----Ursprüngliche Nachricht----- Von: laine78 [mailto:meldsa...@hotmail.com] Gesendet: Donnerstag, 3. Mai 2012 21:40 An: users@wicket.apache.org Betreff: Re: Open page in new window when clicking on button I edited my html file to look like this <div align="center"> <input type="submit" wicket:id="back" > <input type="submit" wicket:id="display" onclick="target='_blank';return true;"> </div> The display button now opens up a page in a new window. Now he issue is at any point after I click the display button, the back button also opens up pages in new windows. How do I go about resetting target in the onclick of the back button ie. <input type="submit" wicket:id="bak" onclick="target=????"> -- View this message in context: http://apache-wicket.1842946.n4.nabble.com/Open-page-in-new-window-when-clicking-on-button-tp4606719p4606940.html Sent from the Users forum mailing list archive at Nabble.com. --------------------------------------------------------------------- To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org --------------------------------------------------------------------- To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org