When a user submits a form we take all parameters, encode them and
store encoded string in the database. When the users want to see which
values they submitted we pull the encoded string from the database,
decode it and show values to the user.
Encoding is done with cryptFactory.newCrypt().encryptUrlSafe(str)
Decoding is done with cryptFactory.newCrypt().decryptUrlSafe(encodedStr)
Where cryptFactory = new CachingSunJceCryptFactory("xxxxx");
So, the encoded string was stored in the database with Wicket 1.4.19
and used to work when decoded with 1.4.19. However, now we are on
1.5.9 and we get the following exception during decoding of string
from the database:
org.apache.wicket.util.crypt.AbstractCrypt - Error decoding text:
xxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
at
org.apache.wicket.util.crypt.AbstractCrypt.decryptByteArray(AbstractCrypt.java:150)
at
org.apache.wicket.util.crypt.AbstractCrypt.decryptUrlSafe(AbstractCrypt.java:66)
...
Caused by: javax.crypto.IllegalBlockSizeException: Input length must
be multiple of 8 when decrypting with padded cipher
at com.sun.crypto.provider.SunJCE_f.b(DashoA13*..)
at com.sun.crypto.provider.SunJCE_f.b(DashoA13*..)
at com.sun.crypto.provider.SunJCE_ab.b(DashoA13*..)
at
com.sun.crypto.provider.PBEWithMD5AndDESCipher.engineDoFinal(DashoA13*..)
at javax.crypto.Cipher.doFinal(DashoA13*..)
at org.apache.wicket.util.crypt.SunJceCrypt.crypt(SunJceCrypt.java:94)
at
org.apache.wicket.util.crypt.AbstractCrypt.decryptByteArray(AbstractCrypt.java:146)
... 63 more
Thanks,
Alec
On Sun, Nov 11, 2012 at 5:21 AM, Sven Meier <[email protected]> wrote:
> Where is encodedStr coming from? Are you using Cryptomapper?
>
> Please give us a stacktrace.
>
> Sven
>
>
> On 11/11/2012 02:13 AM, Alec Swan wrote:
>>
>> Hello,
>>
>> After we migrated from 1.4.x to 1.5.x my
>> CachingSunJceCryptFactory.newCrypt().decryptUrlSafe(encodedStr)
>> started returning null. In 1.4.x the same encodedStr parameter was
>> decrypted without problems. We did not change the Java version and are
>> still on 1.6.20.
>>
>> I debugged into AbstractCrypt#decryptSafeUrl(..) and found out that
>> inside of it decryptByteArray(..) call is now throwing the following
>> exception:
>> "javax.crypto.IllegalBlockSizeException: Input length must be multiple
>> of 8 when decrypting with padded cipher"
>>
>> How can we fix this?
>>
>> Thanks,
>>
>> Alec
>>
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