Hi, It is not clear why you have two submit buttons in HTML. I think you need just one - AjaxButton. It will submit the form via Ajax and if errors occur then its #onError(AjaxRequestTarget) will be called. If everything is OK then #onSubmit() will be called. In both cases you have AjaxRequestTarget around to close the ModalWindow.
Martin Grigorov Wicket Training and Consulting https://twitter.com/mtgrigorov On Tue, Apr 21, 2015 at 9:09 AM, Ulrich <for...@gombers.de> wrote: > I have already asked this question > < > http://apache-wicket.1842946.n4.nabble.com/Modal-panel-reloaded-when-selecting-from-DropDownChoice-td4670394.html > > > but maybe it was off topic there. > > The Modal Window provides the method #close(AjaxRequestTarget). But I want > to provide a Button to validate entered data and display a message in case > of error otherwise close. > If I use AjaxSubmitButton() to handle the button the message is not part of > the target and not updated. I I use Link() the message becomes updated but > I > have no means to close the window. > HTML: > > > Java: > > > > -- > View this message in context: > http://apache-wicket.1842946.n4.nabble.com/How-to-close-a-ModalWindow-without-AjaxRequestTarget-tp4670429.html > Sent from the Users forum mailing list archive at Nabble.com. > > --------------------------------------------------------------------- > To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org > For additional commands, e-mail: users-h...@wicket.apache.org > >
