I'm taking surveying, and I'm going to take statics next semester. Several 
days ago I looked at the statics book. One of the early problems is to use 
Table 1 (conversion factors, inside front cover) to express my height in 
millimeters, my mass in kilograms, and my weight in newtons. My bathroom 
scale reads in kilograms and the weight of a kilogram in newtons is built 
into the calculator, so I don't need the table.

The statics book (from what I read of it) and the surveying book both teach 
that if you are given a problem in a certain measuring system, you calculate 
in that system. The professor I have for both surveying and engineering 
teaches that way. The way I learned is that you convert everything to metric 
and then calculate. To be precise:

If a calculation uses a formula in which a constant depends on the measuring 
system used, write the formula in metric, and convert all quantities to 
metric before using the formula.

Two examples:
Soil calculations, which I talked about a few months ago, involve finding how 
much of the void space in a soil is water. The volume is in cubic feet and 
the masses are in pounds. The method I used is to convert the cubic feet to 
liters, using a number that can be read off many measuring tapes, convert the 
pounds to kilograms, using a number found on many packages, and use 1 for the 
density of water. The method the prof used uses the density of water in 
pounds per cubic foot, which I never heard of before. It's fewer numbers, but 
less familiar ones.

In surveying long distances, one needs to correct elevations for curvature and 
refraction. The correction is proportional to the square of the horizontal 
distance. The book gives three constants: one for curvature, one for 
refraction, and one for the sum. Each has three values: one if the distance 
is in kilofeet, one if it's in miles, and one if it's in kilometers. That's 
six numbers to memorize (not nine, since three are the sum of two of the 
other six). To do this problem by converting to metric, you need four 
numbers: one to convert feet to meters (also used in the soil calculation), 
one to convert miles to kilometers, the curvature constant, and the 
refraction constant. The curvature constant is 0.0785, which not 
coincidentally is close to π/40.

So with more and more formulas, the advantage of calculating everything in 
metric is obvious. You need to remember fewer formula constants. You may need 
more numbers per calculation when presented with English units, but the extra 
numbers are conversion factors, which are used in all the calculations when 
data are in English units. When calculating in English units, you still need 
conversion factors. Why then do the books and the prof teach doing 
calculations in English units?

Pierre

Reply via email to