For ease of use, I'd go with file() instead. It'll return the file in an array which is very convenient for flat-file databases.
-Jon J.
p.s. I realize I'm stating the obvious here, but did you verify that the path
"http://virtual1.example.com/data/directory.data"; is where the file is actually located?
From: Wade Preston Shearer <[EMAIL PROTECTED]> Reply-To: [EMAIL PROTECTED] To: BYU UUG Post <[EMAIL PROTECTED]> Subject: [uug] reading a flat-file database in on another Date: Wed, 26 Feb 2003 16:01:59 -0700
i have a script, on...
virtual1.example.com
...that reads a flat-file database...
/data/database.data
which works quite well.
on...
virtual2.example.com
i put the same script, but didn't want to manage two copies of the same database, thus killing the point of having a database. so, instead of putting...
$filename ="data/directory.data";
...in the top of the script, i put...
$filename ="http://virtual1.example.com/data/directory.data";;
...but it didn't work. i'm guessing that there are some security things are prevent this or something, but am not sure. do i not have the syntacs correct?
-wade preston
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