ah! Thanks! I didn't realize that. So the correct way to do it would
be to say:
Foo.prototype.function_name = function foo() { /* blah */ };
eh?
Regards,
-Dhruv.
On Jun 3, 5:59 am, Michael Schwartz <[email protected]> wrote:
> constructor is part of the prototype. You wiped it out by assigning the
> prototype to {}, which has a constructor of object.
>
> On Jun 3, 2012, at 12:00 AM, dhruvbird wrote:
>
>
>
>
>
>
>
> > Hello,
>
> > I see different output for these 2 snippets of code. The only
> > difference between them is that a prototype is defined on one of them,
> > but not on the other.
>
> > // Snippet-1:
> > function Foo() { }
> > var f = new Foo;
> > console.log(f.constructor.name); // Prints "Foo"
>
> > // Snippet-2:
> > function Foo() { }
> > Foo.prototype = { };
> > var f = new Foo;
> > console.log(f.constructor.name); // Prints "Object"
>
> > Any idea why the behaviour changes by just adding a prototype?
>
> > Regards,
> > -Dhruv.
>
> > --
> > v8-users mailing list
> > [email protected]
> >http://groups.google.com/group/v8-users
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