On Sat, 2008-02-16 at 11:43 -0800, Shawn Ferris wrote:
> Hey All -- I'm new to vala and while I've wanted to learn C, I just haven't
> had a need for it. I'm an Oracle DBA and perl+dbi suites me very well. But,
> alas, I want to take the plunge and would like to write some gnome
> applications. I've come quite accustomed to writing OO-Perl and I had been
> looking at C# because the syntax looked very logical to me. But then I ran
> into vala and gotta say, this is the direction I see myself going for two
> reasons.. Again, the syntax looks logical and in the end, it generates C so
> I'll get more fimiliar with that as well. Best of both worlds. 8D
>
> That being said.. I'm sure I will have a ton of obvious questions... such as,
> string concatenation.. I'm trying this:
>
> public class SMF : GLib.Object {
>
> private const string FOO = "foo";
> private const string BAR = "bar";
> private const string BAZ = FOO + BAR;
>
> public static int main () {
>
> message(BAZ);
>
> return 0;
> }
> }
>
> And you'll probably guess that my error is:
>
> error: invalid operands to binary +
>
> And if I try:
>
> private const string BAZ = "%s %s".printf(FOO, BAR);
>
> I get:
>
> error: initializer element is not constant
>
> So.. would someone be so kind as to tell me how this is done? I would
> appreciate it!
>
> Thx
> SMF 8D
>
>
>
>
>
>
>
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Hi Shawn,
vala compiler has a bug when you try to use string concatenation
operator in variable initializers (see
http://bugzilla.gnome.org/show_bug.cgi?id=516287)
As a temporary workaround you can write your example like this:
public class SMF : GLib.Object {
private const string FOO = "foo";
private const string BAR = "bar";
private string BAZ;
public static int main () {
BAZ = FOO + BAR;
message(BAZ);
return 0;
}
}
mind that you have lost the const modifier in BAZ ;)
Bye,
A.
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